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JEE Advanced Model Paper 19 with solutions for online practice
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© examsnet.com
Question : 6
Total: 60
The rms velocity of a gas at T K is ‘x’. The kinetic energy of the gas at the same temperature will be
3
R
T
x
2
M
4
R
2
T
2
2
M
9
R
2
T
2
x
2
M
M
X
2
2
Validate
Solution:
x =
√
3
R
T
M
KE =
3
2
R
t
=
3
2
R
M
×
x
2
R
3
=
M
x
2
2
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