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JEE Advanced Model Paper 17 with solutions for online practice
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Question : 2
Total: 60
A particle of mass m moves from rest along a straight line under the action of a force fvarying with time as f =
f
0
[
1
−
(
t
−
T
T
)
2
]
where
f
0
and T are positive constants. Then,
The speed of the particle after a time 2T is
4
f
0
T
3
m
After time interval of 3T, the particle starts moving backwards
Between time instants 0 and 2T, the acceleration first increases and then decreases
The particle stops at t = 3T
Validate
Solution:
Use the given expression for force to get an expression for acceleration. Integrate this to get anexpression for velocity. Unless otherwise stated about the initial conditions, the velocity turnsout to be V =
f
0
3
m
T
2
[
3
t
2
T
−
t
3
] . Use this to get the required results
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