Test Index

Application of Integration

Section: Mathematics

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Question : 26

Total: 28

Let f be a non-negative function defined on the interval [0, 1]. If

√1−(f′(t))2dt =

f (t) dt , 0 ≤ x ≤ 1, and f (0) = 0 , then

[JEE Adv 2009 P1]

f (
1
2
) <
1
2
and f (
1
3
) >
1
3
f (
1
2
) >
1
2
and f (
1
3
) >
1
3
f (
1
2
) <
1
2
and f (
1
3
) <
1
3
f (
1
2
) >
1
2
and f (
1
3
) <
1
3

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