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Section:
Mathematics
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© examsnet.com
Question : 2
Total: 2
Consider the given data with frequency distribution
x
i
3
8
11
10
5
4
f
i
5
2
3
2
4
4
Match each entry in List-I to the correct entries in List-II.
List-I
List-II
(
P
)
The mean of the above data is
(1) 2.5
(
Q
)
The median of the above data is
(2) 5
(R) The mean deviation about the mean of the above data is
(3) 6
(S)
The mean deviation about the
median of the above data is
(4) 2.7
(5) 2.4
The correct option is
[JEE Adv 2023 P1]
(P)
→
(3) (Q)
→
(2) (R)
→
(4) (S)
→
(5)
(
P
)
→
(
3
)
(
Q
)
→
(2) (\R)
→
(1) (\S)
→
(5)
(
P
)
→
(
2
)
(
Q
)
→
(3) (\R)
→
(4) (\S)
→
(1)
(
P
)
→
(3) (\Q)
→
(3) (\R)
→
(5) (\S)
→
(5)
Validate
Solution:
x
.....
3
4
5
8
10
11(ascending order)
f
......
5
4
4
2
2
3
‌
Mean
‌
‌
=
‌
3
×
5
+
8
×
2
+
11
×
3
+
10
×
2
+
5
×
4
+
4
×
4
∕
5
+
2
+
3
+
2
+
4
+
4
‌
=
‌
15
+
16
+
33
+
20
+
20
+
16
∕
20
=
‌
120
∕
20
=
6
‌
Median
‌
‌
=
‌
1
2
(
10
‌
th
‌
+
11
‌
th
‌
‌
observation
‌
)
‌
=
‌
1
2
(
5
+
5
)
=
5
Mean deviation about mean
=
‌
3
×
5
+
2
×
4
+
1
×
4
+
2
×
2
+
4
×
2
+
5
×
3
20
=
‌
54
20
=
2.7
Mean deviation about median
=
‌
2
×
5
+
1
×
4
+
0
+
3
×
2
+
5
×
2
+
6
×
3
20
=
‌
4.8
20
=
2.4
P
→
3
;
Q
→
2
;
R
→
4
;
S
→
5
∴
‌
‌
Option A is correct.
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