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Hyperbola

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Column 1, 2 and 3 contains conics, equations of tangents to the conics and points of contact, respectively.

Column 1

Column 2

Column 3

(I) x2+y2=a2

(i) my=m2x+a

(Q)(

a

m2

,

2a

m

)

(II) x2+a2y2=a2

(ii) y=mx+a√m2+1

(Q) (

−ma

√m2+1

,

a

√m2+1

)

(III) y2=4ax

(iii) y=mx+√a2m2−1

(R) (

−a2m

√a2m2+1

,

1

√a2m2+1

)

(IV) x2−a2y2=a2

(iv) y=mx+√a2m2+1

(S) (

−a2m

√a2m2−1

,

−1

√a2m2−1

)

Section: Mathematics

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Question : 5

Total: 15

The tangent to a suitable conic (Column 1) at (√3,

) id found to be √3x+2y=4,then which of the following options is the only CORRECT combination ?

[JEE Adv 2017 P1]

(IV) (iii) (S)
(II) (iii) (R)
(II) (iv) (R)
(IV) (iv) (S)

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