Given sz+tz+r=0...(1)On taking conjugate sz+tz+r=0......(2)From (1) and (2) eliminating zz(∣s∣2−∣t∣2)=rt−rsA) If ∣sâˆ£î€ =∣t∣ then z has unique valueB) If ∣s∣=∣t∣ then rt−rs may or may not be zero so L may be empty setC) locus of z is null set or singleton set or a line in all cases it will intersect given circle at most two pointsD) In this case locus of z is a line so L has infinite elements