Test Index

Solid State

Section: Chemistry

Question : 6 of 19

Marks: +1, -0

Solution:

Contribution of

M = \frac{1}{2} \times 2 = 1

Contribution of

X = \frac{1}{4} \times 4 = 1

Formula = MX

Distance between

M

and

X = \sqrt{ \frac{a^{2}}{4} + \frac{a^{2}}{2} }

= \sqrt{ \frac{3}{4} } a = \frac{ \sqrt{3} }{2} a

= 0.866 a

Both cation and anion have same co-ordination number, i.e., 8.

Assuming, anions are in contact, the ratio of ionic radii of cation M to anion X is 0.732, the minimum radius ratio for a cubical void.

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