The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is List-I List-II (P) Passing {H}₂{S} in the presence of {NH}₄{OH} (1) {Cu}²+} (Q) ({NH}₄)₂{CO}₃ in the presence of {NH}₄{OH} (2) {Al}³+} (R) {NH}₄{OH} in the presence of {NH}₄{Cl} (3) {Mn}²+} (S) Passing {H}₂{S} in the presence of dilute HCl (4) {Ba}²+} (5) {Mg}²+} [JEE Adv 2025 P1]

Question

Examsnet · Accepted Answer

Correct Answer is : P→3;Q→4;R→2;S→1{P} arrow 3 ; {Q} arrow 4 ; {R} arrow 2 ; {S} arrow 1P→3;Q→4;R→2;S→1

	List-I		List-II
(P)	Passing $\mathrm{H}_2\mathrm{S}$ in the presence of $\mathrm{NH}_4\mathrm{OH}$	(1)	$\mathrm{Cu}^{2+}$
(Q)	$(\mathrm{NH}_4)_2\mathrm{CO}_3$ in the presence of $\mathrm{NH}_4\mathrm{OH}$	(2)	$\mathrm{Al}^{3+}$
(R)	$\mathrm{NH}_4\mathrm{OH}$ in the presence of $\mathrm{NH}_4\mathrm{Cl}$	(3)	$\mathrm{Mn}^{2+}$
(S)	Passing $\mathrm{H}_2\mathrm{S}$ in the presence of dilute HCl	(4)	$\mathrm{Ba}^{2+}$
		(5)	$\mathrm{Mg}^{2+}$

Salt Analysis