P = [FeF
6]
3− ox. no. of Fe = +3, configuration: - 3d
5 4S
D As F
− is weak ligand, pairing does not take place,
so it has 5 unpaired electron
Q = [V(H
2O)
6]
2+ , ox. no. of V = +2, configuration: - 3d
3 4S
D It has 3 unpaired electrons
R = [Fe(H
2O)
6]
2+ , ox. no. of Fe = +2, configuration: - 3d
6 4S
D As H
2O is weak ligand, pairing does not take place, so it has 4 unpaired electron
⇒ order of spin only magnetic moment ⇒ Q < R < P