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Chemical Kinetics and Nuclear Chemistry
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Section:
Chemistry
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© examsnet.com
Question : 14
Total: 33
According to the Arrhenius equation,
[JEE Adv 2016 P1]
A high activation energy usually implies a fast reaction
Rate constant increase with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy
Higher the magnitude of activation energy, stronger is the temperature dependence of therate constant
The pre-exponential factor is a measure of the rate at which collisions occur, irrespective oftheir energy.
Validate
Solution:
(A)
K
=
A
e
−
E
a
R
T
High
E
a
means less k, hence slower rate
(B)
e
−
E
a
R
T
=
fraction of molecules having kinetic energy greater than activation energy which increase as temperature increases.
(C) In
k
2
k
1
=
E
a
R
[
1
T
1
−
1
T
2
]
i.e.,in
k
2
k
1
∝
E
a
(D) Rate of reaction ∝ Total number of collision × Fraction of collisions which can form product
Rate of reaction
∝
Z
A
B
×
(
P
*
e
−
E
a
R
T
)
∝
A
e
−
E
a
R
T
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