Test Index

Structure of Atom

Section: Chemistry

Question : 6 of 24

Marks: +1, -0

\mathrm{H}_2

E_0

^{-1}

d = d_0

10^{23}

^{-1}

Solution:

Potential energy of H-atom is taken as zero when electron and nucleus are at infinite distance (given).

∴ P.E. of a H-atom with electron in its ground state

= – 27.2 eV (from Bohr's Model)

At internuclear distance '

d_0

; electron-electron repulsion and nucleus-nucleus repulsion are absent.

∴ P.E. of two H-atom = – 2 × 27.2 eV = – 54.4 eV

= -\frac{54.4 \times 1.6 \times 10^{-19} \times 6.023 \times 10^{23}}{1000} \mathrm{kJ/mol}

= -5242.42 \mathrm{kJ/mol}

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