According to the reaction P4​+NaOH+3H2​O → PH3​+3NaH2​PO2​ oxidation state of phosphorus in P4​ is zero while in PH3​ it is −3 and in NaH2​PO2​, it is +1. This shows that this is a type of disproportionation reaction because there is an increase as well as decrease in the oxidation state of phosphorus.