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JEE Advanced 2021 Paper 2

Section: Physics

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Question : 3

Total: 57

For a prism of prism angle θ=60∘, the refractive indices of the left half and the right half are, respectively, n1 and n2 ( n2≥n1 ) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1=n2=n=1.5. For the case of unequal refractive indices n1=n and n2=n+∆n (where ∆n≪n ), the angle of emergence e=i+∆e. Which of the following statement(s) is (are) correct?

[JEE Adv 2021 P2]

The value of ∆e (in radians) is greater than that of ∆n
∆e is proportional to ∆n
∆e lies between 2.0 and 3.0 milliradians, if ∆n=2.8×10−3
∆e lies between 1.0 and 1.6 milliradians, if ∆n=2.8×10−3

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