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JEE Advanced 2021 Paper 2
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Section:
Chemistry
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© examsnet.com
Question : 24
Total: 57
The pair(s) of complexes wherein both exhibit tetrahedral geometry is(are) (Note:
p
y
=
pyridine Given: Atomic numbers of Fe, Co, Ni and Cu are 26, 27, 28 and 29 , respectively)
[JEE Adv 2021 P2]
[
F
e
C
l
4
]
−
and
[
F
e
(
C
O
)
4
]
2
−
[
C
o
(
C
O
)
4
]
−
and
[
C
o
C
l
4
]
2
−
[
N
i
(
C
O
)
4
]
and
[
N
i
(
C
N
)
4
]
2
−
[
C
u
(
p
y
)
4
]
+
and
[
C
u
(
C
N
)
4
]
3
−
Validate
Solution:
(a)
[
F
e
C
l
4
]
−
F
e
⇒
[
A
r
]
3
d
6
4
s
2
F
e
+
3
⇒
[
A
r
]
3
d
5
4
s
0
C
l
−
is weak field ligand, So pairing does not take place.
∴ In
[
F
e
C
l
4
]
−
[
F
e
(
C
O
)
4
]
2
−
F
e
⇒
[
A
r
]
3
d
6
4
s
2
F
e
−
2
⇒
[
A
r
]
3
d
8
4
s
2
∴ In
[
F
e
(
C
O
)
4
]
2
−
(b)
[
C
o
(
C
O
)
4
]
−
C
o
⇒
[
A
r
]
3
d
7
4
s
2
C
o
−
1
⇒
[
A
r
]
3
d
8
4
s
2
∴
I
n
[
C
o
(
C
O
)
4
]
−
[
C
o
C
l
4
]
2
−
C
o
⇒
[
A
r
]
3
d
7
4
s
2
C
o
+
2
⇒
[
A
r
]
3
d
7
4
s
0
∴ In
[
C
o
C
l
4
]
2
−
(c)
[
N
i
(
C
O
)
4
]
N
i
⇒
[
A
r
]
3
d
8
4
s
2
N
i
0
⇒
[
A
r
]
3
d
8
4
s
2
∴ In
[
N
i
(
C
O
)
4
]
[
N
i
(
C
N
)
4
]
2
−
N
i
⇒
[
A
r
]
3
d
8
4
s
2
N
i
+
2
⇒
[
A
r
]
3
d
8
4
s
0
C
N
−
is strong field ligand, so pairing does not take place.
∴ In
[
N
i
(
C
N
)
4
]
2
−
(d)
[
C
u
(
p
y
)
4
|
+
C
u
⇒
[
A
r
]
3
d
10
4
s
1
C
u
+
⇒
[
A
r
]
3
d
10
4
s
0
∴ In
[
C
u
(
p
y
)
4
]
+
[
C
u
(
C
N
)
4
]
3
−
C
u
⇒
[
A
r
]
3
d
10
4
s
1
C
u
+
⇒
[
A
r
]
3
d
10
4
s
0
C
N
−
is so pairing occurs.
∴ In[
[
C
u
(
C
N
)
4
]
3
−
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