In weak basic solution, permanganate ion converts into MnO2 (reduction of potassium permanganate) and iodine ion converts into iodide ( oxidation of KI) i.e., chemical reaction is written as .. MnO4−+I−⇔MnO2+I2 so equivalents of potassium permanganate = equivalents of I2 given no of moles of potassium permanganate =4 let n moles of I2 released for 4 moles of potassium permanganate consumed. we know, equivalents = no of moles ×n-factor so no of moles of KMnO4×n-factor of it= no of moles of I2×n-factor of it ⇒4×3=n×2 ⇒n=6 Therefore 6 moles of I2 released for 4 moles of KMnO4 consumed.