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JEE Advanced 2020 Paper 1
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© examsnet.com
Question : 43
Total: 54
Let the function
f
:
R
→
R
be defined by
f
(
x
)
=
x
3
−
x
2
+
(
x
−
1
)
‌
sin
‌
x
and let
g
:
R
→
R
be an arbitrary function. Let
f
g
:
R
→
R
be the product function defined by
(
f
,
g
)
(
x
)
=
f
(
x
)
g
(
x
)
.
Then which of the following statements is/are TRUE?
[JEE Adv 2020 P1]
If
g
is continuous at
x
=
1
,
then
f
g
is differentiable at
x
=
1
If
f
g
is differentiable at
x
=
1
,
then
g
is continuous at
x
=
1
If
g
is differentiable at
x
=
1
,
then
f
g
is differentiable at
x
=
1
If
f
g
is differentiable at
x
=
1
,
then
g
is differentiable at
x
=
1
Validate
Solution:
If
f
g
is differentiable at
x
=
1
,
then
lim
h
→
0
f
g
(
1
+
h
)
−
f
g
(
1
)
h
exists finitely
⇒
lim
h
→
0
h
[
(
1
+
h
)
2
+
sin
(
1
+
h
)
‌
g
(
1
+
h
)
]
−
0
h
exists finitely
⇒
lim
h
→
0
(
1
+
sin
‌
1
)
g
(
1
+
h
)
exists finitely
So
lim
h
→
0
+
g
(
1
+
h
)
=
lim
h
→
0
−
g
(
1
+
h
)
⇒
it does not mean that
g
(
x
)
is continuous or differentiable at
x
=
1
But if
g
(
x
)
is continuous or differentiable at
x
=
1
then
lim
h
→
0
+
g
(
1
+
h
)
=
lim
h
→
0
−
g
(
1
+
h
)
,
hence
f
g
(
x
)
will be differentiable
© examsnet.com
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