With the help of calculation of free energy ∆G10=−nFε0=−(1)(F)(0.771V)=−0.771V ∆G20=−(2)(F)(0.44)=0.88FV ∆G30=−(3)(F)(ε0)=−3Fe0V The free energy change for the unknown process can be obtained as ∆G30=∆G10+∆G20 −3Fε0=−0.771F+0.88F=0.109F or ε0=−‌
