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JEE Advanced 2017 Paper 2
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Section:
Chemistry
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© examsnet.com
Question : 19
Total: 54
For the following cell.
Z
n
(
s
)
|
Z
n
S
O
4
(
a
q
)
|
|
C
u
S
O
4
(
a
q
)
|
C
u
(
s
)
When the concentration of
Z
n
2
+
is 10 times the concentration of
C
u
2
+
,
the expression
C
u
2
+
,
the expression for ΔG (in J
m
o
l
−
1
) is
[F is Faraday constant; R is gas constant; T is temperature;
E
°
(
c
e
l
l
)
=
1.1
V]
[JEE Adv 2017 P2]
2.303 RT -2.2 F
2.303RT+1.1F
1.1 F
-2.2F
Validate
Solution:
Z
n
(
s
)
+
C
u
S
O
4
(
a
q
)
→
Z
n
S
O
4
(
a
q
)
+
C
u
(
s
)
E
=
E
°
−
2.303
R
T
2
F
l
o
g
[
Z
n
2
+
]
[
C
u
2
+
]
=
1.1
−
2.303
R
T
2
F
l
o
g
10
=
1.1
−
2.303
R
T
2
F
Δ
G
=
−
2
F
E
=
−
2
F
(
1.1
−
2.303
R
T
2
F
)
=
−
2.2
F
+
2.303
R
T
=
2.303
R
T
−
2.2
F
© examsnet.com
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