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JEE Advanced 2014 Paper 1
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© examsnet.com
Question : 9
Total: 60
A light source, which emits two wave lengths
λ
1
=
400
nm and
λ
2
=
600
nm,is used in young's double slit experiment if recorded fringe widths for
λ
1
and
λ
2
are
β
1
and
β
2
and the number of fringes for them within a distance y on one side of the central maximum are
m
1
and
m
2
,respectively,then
[JEE Adv 2014 P1]
β
2
>
β
1
m
1
>
m
2
From the central maximum 3rd maximum of
λ
2
overlaps with 5th minimum of
λ
1
The angular separation of fringes for
λ
1
is grater than
λ
2
Validate
Solution:
β
=
D
λ
d
∵
λ
2
>
λ
1
⇒
β
2
>
β
1
Also
m
1
β
1
=
m
2
β
2
⇒
m
1
>
m
2
Also
3
(
D
d
)
(
600
n
m
)
=
(
2
×
5
−
1
)
(
D
2
d
)
400
n
m
Angular width
θ
=
λ
d
© examsnet.com
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