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IPMAT 2024 Exam Solved Papers
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Question : 18 of 90
Marks:
+1
,
-0
If
∣
x
+
1
∣
+
(
y
+
2
)
2
=
0
| x+1 | +(y+2)^{2}=0
∣
x
+
1∣
+
(
y
+
2
)
2
=
0
and
a
x
−
3
a
y
=
1
a x-3 a y=1
a
x
−
3
a
y
=
1
, Then the value of a is
1
5
\frac{1}{5}
5
1
1
2
\frac{1}{2}
2
1
1
7
\frac{1}{7}
7
1
2
Validate
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