Concept:Simplify the given expression using the law xnxm=xm−n and then add the exponents.Explanation:Rewrite each factor:(xcxb)b+c−a=x(b−c)(b+c−a)(xaxc)c+a−b=x(c−a)(c+a−b)(xbxa)a+b−c=x(a−b)(a+b−c)Sum the exponents:(b−c)(b+c−a)+(c−a)(c+a−b)+(a−b)(a+b−c)Expand each term:(b−c)(b+c−a)=b2−c2−ab+ac(c−a)(c+a−b)=c2−a2−bc+ab(a−b)(a+b−c)=a2−b2−ac+bcAdd them: b2−c2−ab+ac+c2−a2−bc+ab+a2−b2−ac+bc=0So the left side equals x0=1 (for x=0).The equation becomes 1=x, hence x=1.Answer:x=1