(d) Sum of alphabets position in 1st row = 1 + 4 + 1 + 3 + 2 + 2 + 4 + 3 + 3 = 23 Similarly, sum of digits in 2nd row = 1 + 3 + 1 + 2 + 4 + 2 = 13 Since, these are prime numbers, so sum of all given and unknown alphabets in 3rd row should also be a prime no. Thus, 3rd row = 1 + 2 + 3 + 4 + 4 + 3 + 1 + 1 = 19 (taking D option as correct). No other option gives a prime value in such manner, hence correct answer is (D).