which is always < 0.2 but a positive number. Option A=e2−1=7.34−1=6.34 therefore this cannot be the Answer Option B=loge2−1=
log102
log10e
−1=
log102
log102.72−1
We know that the value of
log102
log102.72−1
< 1 1 and therefore value of
log102
log102.72
−1<0 therefore this cannot be the Answer Option C =2log102−1=log104−1 We know that the value of log104<1 and therefore value of log104−1<0 therefore this cannot be the Answer Therefore the Answer is option 'D'