(A) We have (x−3)2dxdy+y = ∫ (x−3)2dx = - ∫ ydy ⇒ x−31 = ln |y| + c So the domain is R→{3}. (B) On substituting x = t + 3, we get −2∫2 (t + 2) (t + 1) t (t - 1) (t - 2) dt = −2∫2t(t2−1)(t2−4)dt = 0 (being odd function) (C) f (x) = 45−(sinx−21)2 The Maximum value occurs when sinx = 1/2. (D) f ′(x) > 0 if cosx > sinx.