IBPS PO Prelims 24 Aug 2025 Shift 1 Solved Paper

Concept:Use relative positions in a linear row and check valid cases.Explanation:Let the total number of persons in the row be $N$.Case 1: R is fourth from the left end, so $R = 4$.Three persons sit between T and R, so $T = 8$.J sits immediately left of T, so $J = 7$.Between J and R there are 2 persons, so persons to the right of M = 0, making M the rightmost person. Hence $M = N$.M sits third to the right of A, so $A = N - 3$.Five persons sit between A and K, so the possible positions of K are $N - 9$ or $N + 3$.$N + 3$ is beyond the row, so $K = N - 9$.Between K and M, there are 8 persons.The same number of persons sit between R and K, so distance between R and K is 9.Thus $K = 4 + 9 = 13$ from the left, and $N - 9 = 13$ gives $N = 22$.So K is the 13th from the left, which is $22 - 13 + 1 = 10$th from the right.Case 2, where R is fourth from the right, is rejected because it gives 7 persons between R and K but 8 persons between K and M.Answer:K is tenth from the right end, i.e., Option A.