IBPS PO Prelims 23 Aug 2025 Shift 3 Solved Paper

Concept:Find each class total using the boy:girl ratio and the number of girls, then compute the required difference.Explanation:For Class B, ratio $B:G = 3:4$ and girls $= 64$.$4$ parts $= 64 \Rightarrow 1$ part $= 16$.Boys $= 3 \times 16 = 48$.Total of Class B $= 48 + 64 = 112$.For Class C, ratio $B:G = 5:6$ and girls $= 48$.$6$ parts $= 48 \Rightarrow 1$ part $= 8$.Boys $= 5 \times 8 = 40$.Total of Class C $= 40 + 48 = 88$.For Class D, ratio $B:G = 7:4$ and girls $= 32$.$4$ parts $= 32 \Rightarrow 1$ part $= 8$.Boys $= 7 \times 8 = 56$.Total of Class D $= 56 + 32 = 88$.For Class E, ratio $B:G = 9:7$ and girls $= 42$.$7$ parts $= 42 \Rightarrow 1$ part $= 6$.Boys $= 9 \times 6 = 54$.Total of Class E $= 54 + 42 = 96$.Total of Class D and B $= 88 + 112 = 200$.Total of Class C and E $= 88 + 96 = 184$.$x = 200 - 184 = 16$.Now, $7x + 224 = 7 \times 16 + 224 = 112 + 224 = 336$.Answer:$336$ (Option B).