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IBPS PO Prelims 23 Aug 2025 Shift 3 Solved Paper

Question Numbers: 78-81

Two publisher X and Y publish different number of books of three writers A, B and C. Number of books publish by Y of writer C is 5 more than the same publisher publish book of writer B. Total number of books published of writer C is 84. Total number of books published by X publisher of three writers together is 95. Number of books published by Y publisher of writer A is 4 more than the number of books published by X of same writer. Number of books published by Y of writer C is n more than the number of books published by X of writer B where n is square of lowest odd prime number. Ratio of number of books published Y of writer A and B is 3:4.

Question : 81 of 100

Marks: +1, -0

If 25% of books of writer A and 25% of books of writer B from both publishers are removed, while number of books of writer C remains unchanged, then find the ratio of total remaining books of publisher X to publisher Y.

87:89
8 : 9
83 : 79
3 : 7
8 : 7

Validate

Solution:

Concept:

Use the given relationships between writers and publishers to find the original book counts, then remove 25% of only writers A and B and compare the remaining totals of publisher X and publisher Y.

Explanation:

Let

Y(A)=3k

and

Y(B)=4k

, since

Y(A):Y(B)=3:4

Given

Y(C)=Y(B)+5

, so

Y(C)=4k+5

Also

Y(C)=X(B)+9

, hence

X(B)=4k-4

Given

X(C)+Y(C)=84

, so

X(C)=84-(4k+5)=79-4k

Given

Y(A)=X(A)+4

, hence

X(A)=3k-4

Total books of publisher X is 95:

(3k-4)+(4k-4)+(79-4k)=95

3k+71=95

, giving

k=8

Original values:

X(A)=20

X(B)=28

X(C)=47

;

Y(A)=24

Y(B)=32

Y(C)=37

After removing 25% of writers A and B from both publishers: remaining X

=20-5+28-7+47=83

Remaining Y

=24-6+32-8+37=79

Required ratio

=83:79

Answer:

83:79

, i.e. option C.

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