IBPS PO Prelims 23 Aug 2025 Shift 3 Solved Paper

Concept:Use the given relationships between the books sold by publishers X and Y to find the number of books of each writer with each publisher, then calculate the unsold books.Explanation:From the chart, let the books sold by publisher Y be: $Y(A) = 3k$, $Y(B) = 4k$.Given $Y(A) : Y(B) = 3 : 4$ and $Y(C) = Y(B) + 5$.So, $Y(C) = 4k + 5$.Also, $Y(C) = X(B) + 9$.Therefore, $X(B) = Y(C) - 9 = (4k + 5) - 9 = 4k - 4$.Given $Y(A) = X(A) + 4$, so $X(A) = 3k - 4$.Total books of writer C sold by both publishers is $84$: $X(C) + Y(C) = 84$.Thus, $X(C) = 84 - (4k + 5) = 79 - 4k$.Total books sold by publisher X is $95$: $X(A) + X(B) + X(C) = 95$.Substituting: $(3k - 4) + (4k - 4) + (79 - 4k) = 95$.Simplifying: $3k + 71 = 95$, so $3k = 24$, giving $k = 8$.Now find all values: $X(A) = 20$, $X(B) = 28$, $X(C) = 47$; $Y(A) = 24$, $Y(B) = 32$, $Y(C) = 37$.Unsold books with publisher X: Writer B: $25\%$ sold, so $75\%$ unsold = $\frac{75}{100} \times 28 = 21$.Writer A: $20\%$ sold, so $80\%$ unsold = $\frac{80}{100} \times 20 = 16$.Total unsold for X = $21 + 16 = 37$.Unsold books with publisher Y: Writer A: $25\%$ sold, so $75\%$ unsold = $\frac{75}{100} \times 24 = 18$.Writer B: $50\%$ sold, so $50\%$ unsold = $\frac{50}{100} \times 32 = 16$.Total unsold for Y = $18 + 16 = 34$.Combined unsold books = $37 + 34 = 71$.Answer:$71$Correct option: D. $71$