Test Index

IBPS PO Mains 5 Nov 2023 Paper

Question Numbers: 42-45

Direction: Read the following information carefully and answer the given questions.

When a word and a number rearrangement machine is given an input line of words and numbers, it arranges them following a rule. The following is an illustration of input and rearrangement.

Input: 7289 CLAY 2854 POUR 5941 ABLE 6217 FLIP 9723 ONUS

Step I: 49398 ABLE 4963 ONUS 251050 CLAY 36326 FLIP 81832 POUR

Step II: 48399 BAKF 4639 PMVR 2155 BKBX 26633 EKJO 28813 OPVQ

Step III: 1221 BKF 1012 PMVR 211 KX 146 KJ 184 PVQ

Step IV: 429 BFK 134 MPRV 119 KX 22 JK 2 PQV

Step V: 432 130 117 20 5

Step V is the last step for the above input. Find out the appropriate steps for the following input.

Input: 8345 UNIT 4972 DROP 3186 EVEN 5294 SOUP 1376 PLAY

Question : 44 of 155

Marks: +1, -0

What is the difference between third largest number obtained in Step III and the fourth smallest number obtained in the same step?

Validate

Solution:

Concept:

In Step III, each number is obtained by adding the even digits and odd digits separately, then writing the two sums together as one number.

Explanation:

The Step II numbers are

44465

68111

2599

21335

, and

4815

For

44465

: even sum

=4+4+4+6=18

, odd sum

=5

, so the Step III number is

185

For

68111

: even sum

=6+8=14

, odd sum

=1+1+1=3

, so the Step III number is

143

For

2599

: even sum

=2

, odd sum

=5+9+9=23

, so the Step III number is

223

For

21335

: even sum

=2

, odd sum

=1+3+3+5=12

, so the Step III number is

212

For

4815

: even sum

=4+8=12

, odd sum

=1+5=6

, so the Step III number is

126

Thus the Step III numbers are

185

143

223

212

, and

126

Arranging in ascending order:

126

143

185

212

223

. The fourth smallest is

212

Arranging in descending order:

223

212

185

143

126

. The third largest is

185

Required difference

= 212 - 185 = 27

Answer:

27

(Option C).

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