IBPS PO Mains 5 Nov 2023 Paper

Concept:Use the given percentages and total attempts to find $B + D$, then apply both conditions to get D's exact attempts.Explanation:Total questions attempted in the test $= 800$.A attempts $25\%$ of $800 = 200$.C attempts $24\%$ of $800 = 192$.So, B and D together attempt $800 - (200 + 192) = 408$.Let D attempt $d$ questions and B attempt $b$ questions.Thus, $b + d = 408$.From Statement I: D is highest and B is second highest.So, $d > b > 200$ because B must exceed both A and C.With $b + d = 408$ and $d > b$, the possible integer pairs are:$(b, d) = (201, 207), (202, 206), (203, 205)$.So, Statement I alone does not give a unique value for $d$.From Statement II: The difference between B and D is neither $2$ nor $6$.Alone, this is not sufficient because many differences are allowed.Combining both statements: The only pair from Statement I whose difference is not $2$ or $6$ is $(202, 206)$, which has difference $4$.Therefore, D attempted $206$ questions.Answer:Both statements I and II together are necessary. Option C.