IBPS PO Mains 12 Oct 2025 Shift 1 Paper

Concept:The code consists of a symbol based on the word length and a digit based on the number of distinct consonants in the word.Explanation:First, count the total number of letters in each word to fix the symbol.A word with 8 letters is coded as $\$$, 7 letters as $\#$, 6 letters as $\&$, 5 letters as $\%$, and 4 letters as $@$.The word “airport” has 7 letters, so its symbol is $\#$.The word “banana” has 6 letters, so its symbol is $\&$.Next, count only the distinct consonants, ignoring repeated consonants.In “airport”, the consonants are r, p, r, t; the distinct consonants are r, p and t, giving the digit 3.In “banana”, the consonants are b, n, n; the distinct consonants are b and n, giving the digit 2.So, “airport” is coded as $\#3$ and “banana” is coded as $\&2$.Answer:The code for “airport banana” is $\#3\ \&2$.Hence, the correct option is E.