IBPS PO Mains 12 Oct 2025 Shift 1 Paper

Concept:Find City X's total consumers and the male-female difference, then apply the condition $M < 600$.Explanation:From City A, alcoholic total is $400$ and $M - F = 200$.With $M + F = 400$, solving gives $M = 300$ and $F = 100$.From City C, non-alcoholic total is $180$, and $M : F = 1 : 2$.So $M = 60$ and $F = 120$.For City B, total males are $200 + 80 = 280$ and total females are $300 + 120 = 420$.Thus the difference in City B is $420 - 280 = 140$.Now for City X:Alcoholic consumers in X $= 2 \times 400 = 800$.Non-alcoholic consumers in X $= \frac{7}{3} \times 180 = 420$.Total consumers in X $= 800 + 420 = 1220$.So we have $M + F = 1220$ and $|M - F| = 140$.Case 1: $M - F = 140$ gives $M = 680$, $F = 540$.Case 2: $F - M = 140$ gives $F = 680$, $M = 540$.Since males in City X are less than $600$, the valid case is $M = 540$ and $F = 680$.Answer:The number of females in City X is $680$, which is greater than $650$.Hence, the correct option is Option E: Greater than 650.