IBPS Clerk Mains 29 Nov 2025 Paper

Concept:Apply the rule that Draw : Loss is either $2:1$ or $1:1$, with Loss $\le 5$, to determine each player's exact Draw and Loss values.Explanation:For each player, Matches Played $=$ Win $+$ Draw $+$ Loss.Player A: Draw $+$ Loss $= 40 - 30 = 10$.Only valid case: Draw $=$ Loss $= 5$.Player B: Draw $+$ Loss $= 48 - 42 = 6$.Both cases are valid: (Draw $= 3$, Loss $= 3$) or (Draw $= 4$, Loss $= 2$).Player C: Draw $+$ Loss $= 36 - 24 = 12$.Draw $=$ Loss gives Loss $= 6$, invalid since Loss $\le 5$.Draw $= 2 \times$ Loss gives Loss $= 4$, valid, so Draw $= 8$, Loss $= 4$.Player D: Draw $+$ Loss $= 16 - 12 = 4$, so Draw $= 2$, Loss $= 2$.Player E: Draw $+$ Loss $= 30 - 22 = 8$, so Draw $= 4$, Loss $= 4$.Given: difference between matches lost by B and C is more than $1$.C's Loss $= 4$.If B's Loss $= 3$, then $|3 - 4| = 1$, which is not more than $1$.If B's Loss $= 2$, then $|2 - 4| = 2 > 1$, so this case is valid.Hence B's Draw $= 4$ and Loss $= 2$.Sum of draws of A and B $= 5 + 4 = 9$.Answer:$9$, i.e., Option C.