Since we are trying to find the width of the deck, let
x= the width of the deck. Therefore,
x+x+20 or
2x+20 is the width of the entire figure. In the same way,
x+x+28 or
2x+28 is the length of the entire figure.
The area of a rectangle is length
× width, so use
A=l×w. Substitute into the equation:
884=(2x+20)(2x+28) Multiply using FOIL:
884=4x2+56x+40x+560 Combine like terms:
884=4x2+96x+560Subtract 884 from both sides:
884−884=4x2+96x+560−8840=4x2+96x−324 Divide each term by 4:
0=x2+24x−81Factor the trinomial:
0=(x+27)(x−3) Set each factor equal to zero and solve:
x+27=0 or
x−3=0x =−27x=3 Since we are solving for a length, the solution of -27 must be rejected. The width of the deck is 3 feet.