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GATE Electrical Engineering (EE) 2018 Solved Paper
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© examsnet.com
Question : 43
Total: 65
The figure shows two buck converters connected in parallel. The common input dc voltage for the converters has a value of
100
V
. The converters have inductors of identical value. The load resistance is
1
Ω
. The capacitor voltage has negligible ripple. Both converters operate in the continuous conduction mode. The switching frequency is
1
k
H
z
, and the switch control signals are as shown. The circuit operates in the steady-state. Assuming that the converters share the load equally, the average value of
i
s
t
, the current of switch
S
1
(in ampere) is ___________(upto 2 decimal places).
Your Answer:
Validate
Solution:
V
0
=
D
V
s
=
0.5
×
100
=
50
V
I
0
=
V
0
R
P
0
=
V
0
I
0
=
2500
W
By power conversion
V
S
I
S
(
a
v
g
)
=
V
0
I
0
Since both the converter share equal current
I
S
(
avg
)
=
12.5
A
© examsnet.com
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