No. of host =1500 No. of host bits =[log21500]=11 bits ∴ Total possible hosts =211=23×28n is the netmask bits, Range of addresses is =232−n211=232−π Available IP address ⇒202.61 .0 .0 /17
So the IP address follow the pattern 0.0 to 7.2558.0 to 15.25516.0 to 23.255 ⋮ 64.0 to ... ⋮ 104.0 to … ∴ The possible IP addresses are 202.61.64.0/21 & 202.61.104.0/21