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GATE Civil Engineering (CE) 2018 Shift 1 Solved Paper
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© examsnet.com
Question : 56
Total: 65
A conventional drained triaxial compression test was conducted on a normally consolidated clay sample under an effective confining pressure of 200 KPa. The deviator stress at failure was found to be
400
k
P
a
. An identical specimen of the same clay sample is isotropically consolidated to a confining pressure of
200
k
P
a
and subjected to standard undrained triaxial compression test. If the deviator stress at failure is
150
k
P
a
, the pore pressure developed (in kPa, up to one decimal place) is
Your Answer:
Validate
Solution:
Ist Specimen : Drained condition
σ
3
=
200
k
P
a
:
σ
d
=
400
k
P
a
:
σ
1
=
600
k
P
a
II
‌
‌
nd
‌
Specimen : Undrained condition
σ
3
=
200
k
P
a
:
σ
d
=
150
k
P
a
:
σ
1
=
σ
3
+
σ
d
=
350
k
P
a
Let pore pressure developed is u
∴
‌
‌
σ
3
=
(
200
−
u
)
σ
1
=
(
350
−
u
)
From stress relationship
σ
1
=
σ
3
tan
2
(
45
∘
+
‌
φ
2
)
+
2
c
‌
tan
(
45
∘
+
‌
φ
2
)
For clay under drained condition
∴
‌
‌
σ
1
=
σ
3
tan
2
(
45
∘
+
‌
φ
2
)
600
=
200
tan
2
(
45
∘
+
‌
φ
2
)
φ
=
30
∘
For second specimen,
σ
1
=
σ
3
tan
2
(
45
∘
+
‌
φ
2
)
(
350
−
u
)
=
(
200
−
u
)
tan
2
(
45
∘
+
‌
30
∘
2
)
u
=
125
k
P
a
© examsnet.com
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