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AP and TS EAMCET Engineering 2020 Model Paper 1
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© examsnet.com
Question : 2
Total: 160
The solution of
y
11
+
y
1
=
1
y
=
x
−
a
e
−
x
+
b
y
=
x
+
a
e
−
x
+
b
y
+
x
=
a
e
−
x
+
b
y
+
x
=
a
e
x
+
b
Validate
Solution:
Let
y
1
=
v
⇒
y
11
=
d
v
d
x
Therefore
d
v
d
x
+
v
=
1
,
I
.
F
=
9
∫
1
d
x
=
e
x
V
(
e
x
)
=
∫
1.
e
x
d
x
=
e
x
+
a
y
1
=
1
+
a
e
−
x
y
=
x
−
a
e
−
x
+
b
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