The pairs of straight lines x²-3 x y+2 y²=0 and x²-3 x y+2 y²+x-2=0 form a

Correct Answer is : parallelogram

Correct Answer is : parallelogram

Test Index

EAMCET Engineering 2009 Solved Paper

Section: Mathematics

Question : 128 of 160

Marks: +1, -0

x^2-3 x y+2 y^2=0

x^2-3 x y+2 y^2+x-2=0

Solution:

Given pair of lines are

x^2-3 x y+2 y^2=0

and

\;x^2-3 x y+2 y^2+x-2=0 .

\therefore \;\; (x-2 y)(x-y)=0

and

\;\; (x-2 y+2)(x-y-1)=0

\Rightarrow x-2 y=0, \;\; x-y=0

and

x-2 y+2=0

x-y-1=0

Since, the lines

x-2 y=0, x-2 y+2=0

and

x-y=0, x-y-1=0

are parallel.

Also, angle between

x-2 y=0

and

x-y=0

is not

90^{\circ}

\therefore

It is a parallelogram.

Go to Question:

Prev Question

Next Question