The equation of lines are x−y−2‌=0 . . . (i) x+y−4‌=0 . . . (ii) ‌ and ‌‌‌x+3y‌=6 . . . (iii) On solving Eqs. (i) and (ii), we get x=3,y=1 On putting these value in Eq. (iii) 3+3=6 which is satisfied. Thus the required point is (3,1).