Since, the line 3x−2y+6=0 meets the coordinates axes, therefore ∴ Points are A(−2,0) and B(0,3). ∵‌ Radius ‌=AB=√22+32=√13 ∴ The equation of circle, whose centre (−2,0) and radius √13, is ‌(x+2)2+(y−0)2‌=(√13)2 ⇒‌x2+y2+4x+4‌=13 ⇒‌x2+y2+4x−9‌=0