We are getting a odd number of point, if it will comes (two head, one tail and three tail) ‌∵‌‌P(H)=P(T)=‌
1
2
‌∴‌ Required probability = Probability of getting two ‌ ‌‌ heads and one tail + Probability of all three tails ‌ ‌‌‌‌‌=‌3C2(‌