Concept:Second derivative at a point is found by differentiating twice and substituting the value.Explanation:Given f(x)=3x3−5x2+2x−8. First derivative: f′(x)=9x2−10x+2. Second derivative: f′′(x)=18x−10. Evaluate at x=1: f′′(1)=18(1)−10=8.Answer:f′′(1)=8, which corresponds to option B.