Where, n= number of small triangles H = number of ‘end to end’ horizontal lines → In, ∆ABC:
n= number of small triangles = 3 H = number of ‘end to end’ horizontal lines = 1 (BC,) Triangles = 3×23+1×1=6 Hence, Total triangles in ∆ABC = 6 →Now Adding all the ∆s: Total ∆s = 12 + 6 = 18 Hence, the correct answer is 18.