CTET Paper II (Mathematics and Science) Dec 2019 Solved Paper

Concept:Follow the order of operations (BODMAS): simplify brackets first, then multiplication and division from left to right, then addition and subtraction.Explanation:Convert all mixed fractions to improper fractions:$6\frac{2}{3} = \frac{20}{3}$, $2\frac{1}{2} = \frac{5}{2}$, $3\frac{3}{4} = \frac{15}{4}$, $5\frac{1}{2} = \frac{11}{2}$, $4\frac{1}{4} = \frac{17}{4}$, $1\frac{2}{3} = \frac{5}{3}$.Inside the bracket, first multiply: $\frac{3}{4} \times \frac{2}{3} = \frac{1}{2}$.Then add: $\frac{7}{8} + \frac{1}{2} = \frac{7}{8} + \frac{4}{8} = \frac{11}{8}$.Multiply outside: $\frac{5}{3} \times \frac{11}{8} = \frac{55}{24}$.Now perform multiplications from left: $\frac{5}{2} \times \frac{15}{4} = \frac{75}{8}$ and $\frac{11}{2} \times \frac{17}{4} = \frac{187}{8}$.Rewrite the expression: $\frac{20}{3} + \frac{75}{8} - \frac{187}{8} + \frac{55}{24}$.Combine the fractions with denominator 8: $\frac{75}{8} - \frac{187}{8} = -\frac{112}{8} = -14$.Convert $\frac{20}{3}$ and $\frac{55}{24}$ to common denominator 24: $\frac{20}{3} = \frac{160}{24}$, $\frac{55}{24}$ remains, and $-14 = -\frac{336}{24}$.Add: $\frac{160}{24} - \frac{336}{24} + \frac{55}{24} = \frac{160 - 336 + 55}{24} = \frac{-121}{24}$.Simplify: $\frac{-121}{24} = -5\frac{1}{24}$.Answer:Option C. $-5\frac{1}{24}$