In a quadrilateral ABCD, if AB DC, B = 70^ and AB = CD, then :

Correct Answer is : ∠B=70∘ B = 70^∠B=70∘

In a quadrilateral ABCD, if AB DC, B = 70^ and AB = CD, then :

Correct Answer is : ∠B=70∘ B = 70^∠B=70∘

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CTET Paper II (Mathematics and Science) 8 Feb 2026 Shift 1 Solved Paper

Question : 58 of 150

Marks: +1, -0

AB \parallel DC,\angle B = 70^\circ

and AB = CD, then :

$\angle B = 70^\circ$
$\angle A = 70^\circ, \angle D = 110^\circ$
$\angle C = 70^\circ, \angle D = 110^\circ$
$\angle A = 110^\circ, \angle C = 110^\circ$

Validate

Solution:

Concept:

When one pair of opposite sides in a quadrilateral is both parallel and equal, the quadrilateral is a parallelogram. In a parallelogram, opposite angles are equal and consecutive angles are supplementary (sum to 180°).

Explanation:

Given AB || DC and AB = CD, so ABCD is a parallelogram.

Consecutive angles along transversal BC add to 180°. Since AB || DC, we have ∠B + ∠C = 180°. Given ∠B = 70°, we get ∠C = 180° − 70° = 110°.

In a parallelogram, opposite angles are equal: ∠A = ∠C = 110° and ∠D = ∠B = 70°.

Therefore, ∠A = 110° and ∠C = 110°.

Answer:

Option D:

\angle A = 110^\circ, \angle C = 110^\circ

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