Concept:Solve the linear equation using algebraic operations to find x, then substitute into the given expression.Explanation:Start with: 4−32(x−4)=21(2x+5).Multiply both sides by 6 (LCM of 2 and 3): 24−4(x−4)=3(2x+5).Simplify: 24−4x+16=6x+15, so 40−4x=6x+15.Bring terms: 40−15=6x+4x, i.e., 25=10x.Thus x=1025=25=2.5.Now evaluate 22x+1: substitute x=25.22×25+1=25+1=26=3.Answer:3 (Option C)