CTET Paper I (Classes I to V) 24 Dec 2021 Solved Paper

Concept:To find how many smaller cuboidal boxes fit inside a larger cuboidal box, we compare their volumes after converting all dimensions to the same unit.Explanation:First, convert the large box dimensions from meters to centimeters.$0.5$ m = $50$ cm, $0.25$ m = $25$ cm, and the height is already $18$ cm.Volume of one small biscuit packet = $12 \times 5 \times 3$ cubic cm.Volume of the large box = $50 \times 25 \times 18$ cubic cm.Number of packets that fit = (Volume of large box) ÷ (Volume of one small packet).Calculate: $\frac{50 \times 25 \times 18}{12 \times 5 \times 3}$.Simplify step by step: $50 \div 5 = 10$, $25 \div 5 = 5$ (but careful: we cancel stepwise). Better: $\frac{50}{12} \times \frac{25}{5} \times \frac{18}{3} = \frac{25}{6} \times 5 \times 6 = \frac{25}{6} \times 30 = 25 \times 5 = 125$.Thus, 125 small packets can be packed.Answer:125 biscuits packets (Option B).