CTET Paper I (Classes I to V) 24 Dec 2021 Solved Paper

Concept:An improper fraction has a numerator greater than or equal to its denominator.Explanation:Check each option:Option A: $\frac{1}{5}$ and $\frac{2}{5}$ — both numerators are less than denominators. They are proper fractions.Option B: $\frac{1}{3}$ and $\frac{1}{5}$ — again, numerators are smaller. Proper fractions.Option C: $\frac{7}{5}$ (7 > 5) and $\frac{4}{3}$ (4 > 3). Both are improper fractions.Option D: $4$ is a whole number, and $\frac{1}{8}$ is a proper fraction. Not both improper.Thus, only option C contains two improper fractions.Answer:C. $\frac{7}{5},\frac{4}{3}$