CTET Paper I (Classes I to V) 21 Jan 2024 Shift 2 Solved Paper

Concept:To find the cheapest option, calculate the total cost for each choice by multiplying the number of items or packets by their unit price. Compare the totals.Explanation:Option A: $7.5$ dozen items = $7.5 \times 12 = 90$ items. Each item costs Rs. $750$. Total cost = $90 \times 750 =$ Rs. $67,\!500$.Option B: $75$ dozen items = $75 \times 12 = 900$ items. Each item costs Rs. $7.50$. Total cost = $900 \times 7.50 =$ Rs. $6,\!750$.Option C: $75$ packets at Rs. $750$ each. Total cost = $75 \times 750 =$ Rs. $56,\!250$.Option D: $750$ packets at Rs. $7.50$ each. Total cost = $750 \times 7.50 =$ Rs. $5,\!625$.Comparing all totals: Rs. $67,\!500$, $6,\!750$, $56,\!250$, and $5,\!625$. The smallest is Rs. $5,\!625$ from Option D.Answer:Option D (750 packets of Rs. 7.50 each) costs the least.